2x=3x^2/5

Solution for 2x=3x^2/5 equation:

2x=3x^2/5

We move all terms to the left:

2x-(3x^2/5)=0

We get rid of parentheses

-3x^2/5+2x=0

We multiply all the terms by the denominator


-3x^2+2x*5=0

Wy multiply elements

-3x^2+10x=0

a = -3; b = 10; c = 0;
Δ = b2-4ac
Δ = 102-4·(-3)·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-10}{2*-3}=\frac{-20}{-6}
=3+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+10}{2*-3}=\frac{0}{-6}
=0
$